Wednesday, September 1, 2010

Q5

Assuming that only X and Y logic inputs are available and their complements are not available.Then, what is the minimum number of 2 input NAND gate required to implement X (Ex-OR) Y ?
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2 comments:

  1. Understand your kidsSeptember 7, 2010 at 7:12 AM

    Since the complements of X and Y are not available we can't implement it using NAND gate.It can be implemented by using only OR gate

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  2. juliaSeptember 28, 2010 at 5:19 AM

    I think 4 number of NAND gates are required.

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